P = (number of favourable outcomes) / (total number of outcomes)Total number of outcomes = 2 Nickels + 3 Pennies + 3 Quarters + 2 Dimes = 10 CoinsWe are interested in the probability of selecting dime = 2/10 = 1/5
A jar has ten coins in it. Two of them are nickels, three of them are pennies, three of them are quarters, and two of them are dimes. If one coin is taken out of the jar randomly, what is the probability that it will be a dime?
Overall, there are 10 coins.
2 Nickels, 3 Pennies, 3 Quarters and 2 Dimes.
So we know there's 10.
And we need to know the probability of the coin being a dime.
So we have 2 dimes.
So it is 2/10. Two over ten. (If it asks to simplify it would be 1/5).
Remember when calculating probability to know the total first (in your case you are already given the total).
And then look at the number of the item or whatever you are given, in some cases you need to simplify it, if you're asked to.
2 Nickels, 3 Pennies, 3 Quarters and 2 Dimes.
So we know there's 10.
And we need to know the probability of the coin being a dime.
So we have 2 dimes.
So it is 2/10. Two over ten. (If it asks to simplify it would be 1/5).
Remember when calculating probability to know the total first (in your case you are already given the total).
And then look at the number of the item or whatever you are given, in some cases you need to simplify it, if you're asked to.
2/10 simple fraction! All you do is take the total number (10 in this case) and the number of dimes (2) and make it a fraction 2/10s of a chance it will be a dime.
