A boat is to be manned by eight men of whom 2 of them can only row on bow side and 3 can only row on stroke side.The number of ways in which the crew can be arranged?

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Chris Kimmel Profile
Chris Kimmel answered
Great question!

(4*3)*3=total possible stroke side options
(6*2)*3=total possible bow side options

(4*3)*(6*2)*3 = 432

Explanation 1: The numbers in parentheses are are the ways the one-side only people can be on. The numbers outside the parentheses are the 3 possible ways the floaters that could pick either side could be arranged for each unique combination of one-sided people on each side.

Explanation 2: So we take the options for the one-siders on the left (4*3), the options for the one-siders on the right (6*2), and multiply them. That (144) is the total number of one-side combinations. But each one of those combinations still has three empty seats. So we take that number (144) and multiply by three.

I'm sorry I can't explain further! I did my best. I hope this makes sense.

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